Update ANS: if a+b+c =0 and 1,w,w^2 are three cube roots of unity , then (a+bw+cw^2)^3+( a+bw^2+c^2)^3 is equal to 27abc

29 Jul 2021

if a+b+c =0 and 1,w,w^2 are three cube roots of unity , then (a+bw+cw^2)^3+( a+bw^2+c^2)^3 is equal to 27abc

if a+b+c =0 and 1,w,w^2 are three cube roots of unity , then (a+bw+cw^2)^3+( a+bw^2+c^2)^3 is equal to 27abc UPDATEANS

No comments:

Post a Comment

Please do not enter any spam link

Subscribe to: Post Comments (Atom)

⚡ ANS

Search