Update ANS: 32 sin^6 theta= 10 - 15cos 2 theta + bcos 4 theta - acos 6 theta then prove tan theta tan 5 theta = a+b-5/a-b+7

18 Jun 2022

32 sin^6 theta= 10 - 15cos 2 theta + bcos 4 theta - acos 6 theta then prove tan theta tan 5 theta = a+b-5/a-b+7

32 sin^6 theta= 10 - 15cos 2 theta + bcos 4 theta - acos 6 theta then prove tan theta tan 5 theta = a+b-5/a-b+7

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